InTheShed Grows Inside & Out: Jump In Any Time

LOL, I'm lost in the math! :eek:

Heheh, if you're reading the feed to the panels, they're gonna read 1.05 amps at max.

It's a constant current driver. :rofl:
 
Jesus she’s how dies you head feel with all this info I’ve been scrolling through most of it as I know I should apply more effort to understand what you all are going on about only thing I understood was trying to figure out kilo watt on meter outside to what is running inside and how to determine electrical bill ?
 
@Graytail...If you're lost I feel much better!

So I should be measuring the flow to the driver. Here is my meter:


s-l640.jpg


Next step?
 
@Graytail...If you're lost I feel much better!

So I should be measuring the flow to the driver. Here is my meter:


s-l640.jpg


Next step?
Oh I got one of those meters following lol try too :passitleft:

Wish I could help you but let’s see
 
Crazy gave you the formula P=V*U. You need to measure the voltage first to see where your outlet falls. Then monitor the amperage draw when the light is on. Assuming you are at 120V (which you're probably not. more like 115-118) and applying the formula Watts = Volts * Amperage or P=V*U. you want 250watts so P=250. applying that to the formula based on the assumption that your wall is 120V you get 250 = 120*U. Algebraically solving for it 250/120=U so 250 watts nets 2.0833 amps.

Now here is where it gets fun. This is what the system draws. The meanwell is converting AC to DC and reducing the voltage at the same time. There is a loss in doing this thus the heat created by the driver so even though that is what you're calculating what the strips see is less.

Advice get it close and call it a day. The plants are not going to know the difference between 250 and 230 watts.
 
Crazy gave you the formula P=V*U. You need to measure the voltage first to see where your outlet falls. Then monitor the amperage draw when the light is on. Assuming you are at 120V (which you're probably not. more like 115-118) and applying the formula Watts = Volts * Amperage or P=V*U. you want 250watts so P=250. applying that to the formula based on the assumption that your wall is 120V you get 250 = 120*U. Algebraically solving for it 250/120=U so 250 watts nets 2.0833 amps.

Now here is where it gets fun. This is what the system draws. The meanwell is converting AC to DC and reducing the voltage at the same time. There is a loss in doing this thus the heat created by the driver so even though that is what you're calculating what the strips see is less.

Advice get it close and call it a day. The plants are not going to know the difference between 250 and 230 watts.
Thanks Sam! Much clearer, though I have no idea why we have to use P when we mean watts and U when we mean amps. Some sort of secret electrical code FFS ;).

Watts = Volts x Amps yes? So I first read one of the wires to the driver using the 4A setting and get the amps. Then I switch the meter over to V setting on the same wire and get the volts. Multiply the two and that will give me wall watts which is all I care about. Have I got that right?

I'm not interested in the efficiency of the driver as I already own it!

:thanks:
 
Lmao me too :passitleft:
This is when you wish you had a trade in something besides your everyday job..
i fill for shed gotta be nerve racking theres 2 logical outcomes here
1- itll work which i have faith it will he is in good hands
2- we get a pic of sheds hands all black and bandanged up worst case senario..:rip::hmmmm:

Man so confusing id be pulling my hair out
 
Thanks Sam! Much clearer, though I have no idea why we have to use P when we mean watts and U when we mean amps. Some sort of secret electrical code FFS ;).

Watts = Volts x Amps yes? So I first read one of the wires to the driver using the 4A setting and get the amps. Then I switch the meter over to V setting on the same wire and get the volts. Multiply the two and that will give me wall watts which is all I care about. Have I got that right?

I'm not interested in the efficiency of the driver as I already own it!

:thanks:

Should work that way. I would measure volts at the outlet but your method should work.

I think you just got caught up in the scientific symbols. Engineering in general use them a lot because most equations are factored based on what you are solving for. Then the knowns are applied to the variables and its simple math from there on out.
 
Man so confusing id be pulling my hair out
Anything can be confusing until someone explains it to you in a way you can understand. That's what Sam did.

Should work that way. I would measure volts at the outlet but your method should work.
So just put the probes in the outlet and read the volts with no draw on it?

I think you just got caught up in the scientific symbols. Engineering in general use them a lot because most equations are factored based on what you are solving for. Then the knowns are applied to the variables and its simple math from there on out.
I figured it was some engineering or universal symbols, but for the rest of us, common abbreviations make it so we don't have to sift through the explanations to figure out what we're talking about.

W=V*A is obvious since we're discussing watts, volts, and amps. That's what the meter says as well. P=V*U first needs to be translated into common usage to be understood, which is what you did by writing out the explanation.

:thumb:

And just to make sure...if my voltage is 115, then I want to dial the amps down on the pot until the meter reads 2.17 to get to 250 watts, yes?

250 = 115*2.17
 
Anything can be confusing until someone explains it to you in a way you can understand. That's what Sam did.


So just put the probes in the outlet and read the volts with no draw on it?


I figured it was some engineering or universal symbols, but for the rest of us, common abbreviations make it so we don't have to sift through the explanations to figure out what we're talking about.

W=V*A is obvious since we're discussing watts, volts, and amps. That's what the meter says as well. P=V*U first needs to be translated into common usage to be understood, which is what you did by writing out the explanation.

:thumb:

And just to make sure...if my voltage is 115, then I want to dial the amps down on the pot until the meter reads 2.17 to get to 250 watts, yes?

250 = 115*2.17
Yeah all good tho now buddy..gotta love the help.. now go hit your peace pipe and enjoy some ak47 and throw all the x’s = pain and the second to the third power and the fraction methods to build a rocket ship out the windows and enjoy building her my friend lmao

Yeeeeee haaaaaaa
 
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