This is pieced together from limited knowledge and it could all be wrong.
100 grams of cannabis at 25% total cannabinoid acids would contain and lose 3 grams of CO2 in a total carbolixation.
3 grams is 0.0683 mol.
0.0638 mol of CO2 in a 1 liter container will have
14.81 PSI at 32F
20.25 at 212
20.79 at 230
20.94 at 235
21.09 at 240
21.39 at 250.
These are pressures that are beyond the design limits of a pressure cooker. However they are not all that high. I think city water pressure is in the 50 to 80 range, car tires 30-40.
This has me thinking a large pipe nipple, some Teflon tape, a pressure gauge and another smaller nipple. Tap the larger nipple to make a T with the smaller one and add the gauge. Once you find the volume of the mouse trap, add the appropriate amount of buds, seal it up and immerse in a hot oil bath.
If I have it correct the pressure does not increase all that fast in the range we need.
Then there is the water to contend with.
10% of a 100g sample would be 10g.
1 mol H2O = 18.015g
10g/18.015 = 0.556 mole.
To vaporize 10g of water in a 1L container with the tempter at 235F the pressure would have to be 258PS.
However, all we need to do is bring the water to 235F, the vapor pressure will climb to 20.94PSI and the pressure from the H2O and the CO2 will start condensing the H2O.
CO2 will remain a gas when cooled to room temp and my guess is that most of the H2O vapor will be reabsorbed into the buds.
Of the terpenes I have listed, there are only two that have boiling points below 235F (112.8C). Even those temperatures would be higher with the increased pressure.
If it actually works, it would probably work with fresh harvest.
Let me know what you think.
I never know