Tor,
a little good ol' grade school math will tell you how much area these rotational units get.
the area of a cylinder= circumference x height (or depth in our case since its on its side = 22 inches)
circumference= Pi (3.14) x the Diameter (44 inches).
so. . . for the volks, (3.14)(44 inches)(22 inches)= 3041 square inches
and since there are 144 square inches in a square foot,
3041(in)/144(in/ft)= 21.12 square feet.
which is a bit bigger than a 4' x 5' room (obviously). . . the biggest benifit is obviously positioning. . . every plant is dirctly "under" the bulb, so therefore every plant gets optimal light.
in reality the sides get a bit less. if you used two bulbs however, that would cover the entire garden plus some.
the 2 x 400w system would prob do better than the 1 x 600, but i think im going for 2 x 600 so i can blast the shit out of them, add co2, you know. . . go overboard like i always do.
a little good ol' grade school math will tell you how much area these rotational units get.
the area of a cylinder= circumference x height (or depth in our case since its on its side = 22 inches)
circumference= Pi (3.14) x the Diameter (44 inches).
so. . . for the volks, (3.14)(44 inches)(22 inches)= 3041 square inches
and since there are 144 square inches in a square foot,
3041(in)/144(in/ft)= 21.12 square feet.
which is a bit bigger than a 4' x 5' room (obviously). . . the biggest benifit is obviously positioning. . . every plant is dirctly "under" the bulb, so therefore every plant gets optimal light.
in reality the sides get a bit less. if you used two bulbs however, that would cover the entire garden plus some.
the 2 x 400w system would prob do better than the 1 x 600, but i think im going for 2 x 600 so i can blast the shit out of them, add co2, you know. . . go overboard like i always do.